[vladimir]

can anyone help me with the forensix one step closer

i am at the point of trying to deobfuscate the vbs code and extracting the powershell code but for some reason it seems the powershell code is incomoplete. Please what do i do?

[botdet]

A hint for Apethanto root?

[jackezz42]

some hints in exchange for the how get root flag of Apethanto?

[jackezz42]

some hints in exchange for the how get root flag of Apethanto?

You got the root there ?

no i get only the user flag now i need to get the root flag

[local]

i got root for Apethanto and flags for Great Old Talisman, GateCrash, WindowsOfOpportunity... you can reach me out in exchange for MSS, Nexus Void, One Step Closer, Zombienator

This forum account is currently banned. Ban Length: Permanent (N/A Remaining)
Ban Reason: Leeching.

[Comma]

anyone can help me with crypto MSS easy ?

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

You can get more than one share, if you get enough shares you can get the secret. You have the source, so mess with it locally

This could help https://www.geeksforgeeks.org/implementi...in-python/

---

anyone can help me with crypto MSS easy ?

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

Pmed you

[Bet4]

Looking for help on gatecrash, please

Pm if you want explanation

I can't PM you but I'd also like an explanation if you can!

[local]

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

You can get more than one share, if you get enough shares you can get the secret. You have the source, so mess with it locally

This could help https://www.geeksforgeeks.org/implementi...in-python/

---

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

Pmed you

I can't reply your message.. it's disabled

This forum account is currently banned. Ban Length: Permanent (N/A Remaining)
Ban Reason: Leeching.

[Comma]

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

You can get more than one share, if you get enough shares you can get the secret. You have the source, so mess with it locally

This could help https://www.geeksforgeeks.org/implementi...in-python/

---

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

Pmed you

I can't reply your message.. it's disabled

Hit me up at comma_was_taken@proton.me if u want help. My account's too new to pm lol

[vladimir]

i have almost completed one step closer but got stuck. Who wants my explanation in exchange for apethanto root explanation